$\int8\:tan\:4xdx$

$\frac{\sqrt{x}}{1}+\frac{1}{\sqrt{x+1}}$

$f\left(x\right)=\left(\frac{2x-x}{x-1}\right)^{\frac{1}{4}}$

$\int\frac{x^2-4x+4}{\left(32+4x-x^2\right)^{\frac{3}{2}}}dx$

$\frac{3x^5+4x^3-6x^2}{4x^4-4}$

$x^2-12=13$

$\int\left(\frac{x}{x^2-3x+3}\right)dx$