$\frac{36+12y+y^2}{2}$
$\int_0^{\frac{\pi\:\:}{5}}\left(5\:sec^5x\:tan^3x\right)dx$
$4a^2+12a+8=-2$
$\frac{d}{dx}\left(\sqrt[5]{31}\right)$
$\left(12x+37y\right)\left(37y-45x\right)$
$\left(-2+5+1\right)-\left(-4+3-7\right)+\left(-6+8\right)$
$\frac{2x^4+6x-3}{2x-4}$
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