$\frac{3}{4}x-1\le\frac{1}{2}x+2$
$-10x^2-11x^2$
$-9-3+6\cdot\left(-3\right)$
$limx->0+\left(tan^x\left(1-x^x\right)\right)$
$.5^3$
$\int\left(\frac{x}{\sqrt{x-8}}\right)dt$
$b^2-289$
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