$e^x\cos\left(x\right)-e^x\sin\left(x\right)=0$
$\log\left(15-2x\right)=2\log\left(x\right)$
$\lim_{x\to\infty}\left(\frac{2x+1}{2x}\right)^x$
$5^{-6}\cdot5^9$
$6x^2-8x+3-3x-2$
$12^{54}$
$\left(gf-4\right)\left(gf+4\right)$
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