$\left(\frac{1}{6}x^3-1\right)+\left(x^2-\frac{1}{2}x+\frac{5}{6}\right)+\left(-\frac{1}{3}x^3-\frac{5}{6}x^2+x-\frac{3}{4}\right)$

$\int_1^3\left(e\right)^{2x-1}dx$

$\frac{32-6}{-13}$

$\int\left(\frac{x^3-x^2-x+3}{x^2-3x+2}\right)dx$

$\left(-10\right)\left(-2\right)+15-\left(-4\right)$

$\int\left(\frac{4x}{\left(x-6\right)}\right)dx$

$-4-4-4-4-4-4-4-4-4-4$