$-170+\left(-80\right)+97$
$x^2+3x^2-4^2$
$x-4=-6$
$\lim_{x\to\infty}\left(\frac{\sqrt{x+3-\sqrt{3}}}{x}\right)$
$\frac{\left(4x^5+8x^4-20x^2-40x-23\right)}{4x+4}$
$1-7-2-10-3-8$
$\left(\frac{3}{2}a^2+\frac{5}{4}b^3\right)\left(\frac{3}{2}a^2-\frac{5}{4}b^3\right)$
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