$3x+6\le27$
$\lim_{h\to0}\left(\frac{x-8}{\sqrt[3]{x-2}}\right)$
$\left(8x^7\right)\left(-7x^3\right)\left(x^2\right)$
$f\left(x\right)=\frac{x+3}{\left(x+7\right)\left(x-1\right)}$
$\:6x^2\:+\:11x\:-\:35$
$\left(7a\right)^2\left(-2a\right)^3$
$\frac{\frac{1}{2}}{\frac{1}{\infty}}$
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