$\left(-2xy^2+9xy^3\right)\left(2xy+9xy^3\right)$
$x^2-12x=4$
$\left(8-14\right):\left(\left(7-12\right)+\left(15\:-12\right)\right)x\:7$
$-1228+4304$
$\frac{5}{11}x^3-\frac{2}{11}x^3-\frac{1}{11}x^3$
$x^2+x=8$
$\frac{3^{-1}}{3^{-3}}$
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