$\left(8x^{5}+4b^{2}\right)^{3}$
$-\frac{184}{+2}$
$\lim_{x\to2}\left(\frac{2-\sqrt{6x+16}}{4x^2-9^{2x+4}-7}\right)$
$\int\frac{6x+1}{\sqrt[3]{x+2}}dx$
$- 3 x ^ { 2 } + 6 x + 1 = 0$
$\left(x+2\right).\left(x+5\right)>0$
$\sec^2a\left(1+\sin^2a\right)$
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