$x ^ { 2 } - 2 x - 4 \geq x ^ { 2 } - 3 x + 3$
$4a^5b^2ba^3x$
$6b>24$
$64-\left(56-72:8\right)$
$\left(x-5\right)^{\frac{2}{3}}=9$
$-15x^3+75x^3$
$\lim_{x\to1}\left(\frac{\left(1-x+\ln\left(x\right)\right)}{\left(1+cos\left(3\cdot\pi\right)\right)}\right)$
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