$\int_{e^{-3}}^{e^2}\left(\frac{1}{x\log\left(x\right)}\right)dx$
$x^2=2$
$\frac{3x-4}{3-x}=2$
$\frac{1}{2}a\text{restor}-\frac{3}{4}$
$20=12x-16$
$\frac{dy}{dx}=-1$
$\left(m-12\right)\left(m+7\right)$
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