$\left(3x^5+4x\right)^2$
$1+1\infty$
$\ln\left(\sqrt{\frac{1+4x}{1-4x}}\right)$
$9a^6-25$
$-\left(15+26+8\right)+\left(-5+36-78\right)$
$-50\cdot8$
$\int x\sqrt{36-\left(x-3\right)^2}dx$
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