$x^2+4x^2=\:5x^2$
$1-\tan\left(x\right).\tan\left(y\right)$
$\int\frac{-6x^8}{5}dx$
$\frac{2x}{x^2-1}\:\:-\frac{2}{x-1}$
$\int\frac{3-x}{x\left(x^2-2x+3\right)}dx$
$4x^3\cdot2y^{-2}\cdot5y^5\cdot x^{-8}$
$\left(p-2\right)\left(p-8\right)$
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