$4y^3=6x^2+1$
$\left(a^3-\frac{5}{9}b^3\right)^2$
$4.7x-5.48\ge\:11.44$
$\frac{x-\left(mx\right)}{\sqrt{x}-\sqrt{\left(mx\right)}}$
$\frac{3+sen\left(x\right)}{1-sen^2\left(x\right)}$
$-5-8+3+12-1+1$
$\frac{\sqrt{0}}{0}$
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