$3\tan^2\left(x\right)+4=5$
$\int\frac{\sqrt{p^2-4}}{p^2}dp$
$4x^2\:+\:8x\:-\:32\:=\:0$
$-8x=-24$
$\frac{10x-35+3\left(3x-1\right)}{15}-\frac{5}{3}x=-\frac{4}{3}$
$\left(10\sqrt[2]{5}\right)^2$
$\frac{2}{y+1}+\frac{3}{y-1}$
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