$4+\left(-7\right)\cdot\left(5\right)$

$16x^4y^8z^2-49$

$\int\left(\frac{1}{\left(3x-7\right)^5}\right)dx$

$\left(8x^2-\frac{1}{2}x-\frac{4}{3}\right)-\left(6x^2+\frac{4}{3}x-\frac{1}{2}\right)-\left(\frac{1}{2}x+1\right)$

$\frac{-14}{2}$

$\sqrt[3]{27a^7b^6c^2}$

$-2^2\left(1-2\right)+2\left(5-10\right)$