$5y^2+6y+1$

$\left(3u^4v^3\right)^2$

$\lim_{x\to0}\left(\frac{3x^3}{9x-sen2x}\right)$

$\lim_{x\to-\infty}\left(\frac{x^3+1}{x^2-3x-4}\right)$

$x^2-16-x\:=x^2$

$f\left(x\right)=\left(x+4\right)\left(x-2\right)\left(x-1\right)$

$\int\left(\frac{x}{\sqrt[3]{5x-1}}\right)dx$