$\frac{x}{15}=1$
$\frac{1}{\sin^2\left(x\right)}-7=0$
$\lim_{x\to\infty}\left(3x^2+7\right)^6$
$4\cdot3\left(2\right)-3\cdot3^2\left(-2\right)+5\left(-2\right)^3$
$25n^2-36m^2$
$\left(\frac{x}{2-3y}\right)^2$
$\left(-18x^2-6x+12\right)$
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