$121x^{2\:}-625$
$\left(5x+14y^3\right)^2$
$3por4mas12$
$y^3=\frac{x^3}{3}+2x+c$
$\left(-864\right)-\left(1728\right)$
$.93+.76+.08+8.3+.12$
$\left(x+5\right)^2+5\left(2x+3\right)=2\left(x+4\right)^2$
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