$5\tan3x=2$
$\left(-3x^2+6a\right)\left(3a^2\right)$
$\lim_{x\to4}\left(ln\left(x-3\right)\right)$
$\int sien^3\left(x\right)dx$
$0=\arcsin\left(e^{-\frac{x}{216.086}}\right)$
$\int\left(\frac{5\left(lnx\right)^4}{3x}\right)dx$
$-8\frac{1}{2}^3$
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