$\frac{x^2+3-1}{2}$
$\frac{d}{dx}x^2y^3=x^3y^2+4$
$-.0125+\left(-0354\right)$
$\left(\sqrt{a-4}\right)\left(\sqrt{a+4}\right)$
$2x^2-4x-5>1$
$y'=\left(cos^2xsen2x\right)$
$\sin\left(u\right)+\sin\left(v\right)=1.2$
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