$x^2-9=40$
$y=\frac{x^3}{21}+\frac{7}{4x}$
$\left(2y\:-\:3\right)^2$
$-b-b-b+3b$
$\:x\:\left(x^2-4\right)^5$
$\:3\left(16x^4y^6\right)\left(\:-7x^3y^2\right)$
$3^{-2}\cdot\left(7-4\right)^2+\left(7+4\right)^2$
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