$\left(x+3\right)\frac{dy}{dx}=3$
$\left(\frac{7}{5}mn^2-z^2y\right)^3$
$\frac{1}{3}\left(2\sqrt{x^3-16}\right)$
$\left(4+6xy\right)=5x-12y$
$\frac{d}{dx}\sqrt{\frac{x-2}{x^6+5}}$
$36x^4y^6+6x^2y^5z+\frac{1}{4}y^4z^2$
$y'-2xy=x\:y\left(0\right)=1$
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