$\int\frac{1+x}{4-9x^2}dx$
$e^{\frac{x^2}{2}}\cdot\left(-\frac{6}{x}\right)$
$64x^3+216z^9$
$36x^4+16x-20x^3+28x^6$
$\frac{x}{4x^2}$
$\:-1.6\:and\:-0.4\:is$
$2 x ^ { 3 } - 6 x + 4$
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