$16x^6-2x^3y^2+\frac{y}{16}^2$
$19-2^2$
$\frac{dy}{dx}=x^2+1-\frac{2y}{x}$
$\sin\left(\frac{\pi}{3}\right)^2+\cos\left(\frac{\pi}{3}\right)^2$
$\left(w-r\right)^2\:=w^2-r^2$
$\left(3gn^9\right)^4$
$\frac{dy}{dx}=\sqrt{1-y^2}\frac{d^2y}{dx^2}$
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