$x^6-100$

$\lim_{x\to2}\left(3x^2-5x-2\right)$

$_{\left(sec^2-1\right)^2}$

$\frac{\left(\sec\left(x\right)-5\right)}{1-5\cos\left(x\right)}$

$m^2+m+1=0$

$\left(2x+8\right)\left(2b-8\right)$

$\sin^4\left(x\right)-\cos^4\left(x\right)=\sin^2\left(x\right)-\cos2\left(x\right)$