$-1+y^2-x+3y^2$
$y=\frac{1}{2}x^2-4x+6;x=-8$
$\frac{2.1483}{20.014}$
$a\:+\:2\:<\:-10$
$\lim_{x\to-3}\left(\frac{\left(x^2-3x\right)}{3-x}\right)$
$\lim_{x\to0}\left(\frac{3+x}{x\left(x-8\right)}\right)$
$\tan^2x-10tanx+25$
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