$y=3x^2+4x+2$
$\frac{2mn^2}{4nm^3.-4m^2n^4}$
$\left(m^2-2m^2n+2n^2\right)^2$
$\frac{dy}{dx}=\frac{4y}{x+3}$
$\lim_{x\to-\infty}\left(\frac{x\sqrt{-x}}{\sqrt{1+4x^2}}\right)$
$2x+y-5-5x-2y+1$
$4<2x-3$
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