$\lim_{x\to\infty}\left(\frac{\arctan\left(x^6\right)}{x^8}\right)$
$y'+y=-2$
$2log\left(x+2\right)-log\left(x-4\right)=1$
$1+\frac{2b}{3}+\frac{b^2}{a}$
$14=-7+\frac{u}{3}$
$\int\:\frac{3x^4-2x^3+x^2-10}{x^2+2}dx$
$3a-8b+5a-4c+2a-2a-11b-2c$
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