$a\left(mn^2-6\right)\left(mn^2+3\right)$
$\sin\left(x\right)^2-2=-sin\left(x\right)$
$8^2-12$
$x-\frac{1}{x}=\frac{2}{x}$
$y=125\left(x^2-6x\right)^2$
$\frac{6x-7}{5}>2-3\left(x+1\right)$
$2x^2\:+\:12x\:-\:16\:=0$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!