limx→∞(nln(n)17x2+4)\lim_{x\to\infty}\left(\frac{n\ln\left(n\right)}{17x^2+4}\right)x→∞lim(17x2+4nln(n))
3x−2x+1=2x\frac{3}{x}-\frac{2}{x+1}=\frac{2}{x}x3−x+12=x2
20−15+15−10−7+1+1220-15+15-10-7+1+1220−15+15−10−7+1+12
23≥w−923\ge w-923≥w−9
4⋅3+2⋅5−24\cdot3+2\cdot5-24⋅3+2⋅5−2
limx→∞(arctan(x3)arcsin(1x))\lim_{x\to\infty}\left(\frac{arctan\left(\frac{x}{3}\right)}{arcsin\left(\frac{1}{x}\right)}\right)x→∞lim(arcsin(x1)arctan(3x))
−1728+216-1728+216−1728+216
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