$\frac{\sin\:\left(90^{\circ\:\:}-x\right)}{1+\sin\:\left(x\right)}=\sec\:\left(x\right)-\tan\:\left(x\right)$
$-2x-\frac{1}{3}x$
$x^2-4x-10y-36=0$
$3-2\cdot\left(3\cdot2-4\cdot2\right)+\left(-3\right)\cdot\left(2-5\right)$
$\left(x^4+x^3\right)^{tanx}$
$\sqrt{3x+1}x=0$
$\sqrt{2x+1}+7=2$
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