$6xz\:y\:-xyz2$
$\frac{6^9}{6^3}$
$sec^2x+3=tan^2x+4$
$\frac{dy}{dx}=k\left(78-\frac{6}{7}x\right)\left(14-\frac{1}{7}x\right)$
$\left(20^r-5\right)\:\left(20^r+5\right)$
$\left(\frac{27}{3^2}\right)\left(5\right)$
$\int5x^4\cdot\left(x^5+2\right)^6dx$
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