$\frac{4a^2}{16a^2b}$
$x2+x^2$
$\left(-4\right)^5\left(-4\right)^3$
$\left(3x+2y+c^4\right)^3$
$2a+3>-30+6a$
$m^2+12m+5$
$2u+9=8u+21$
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