$\int\frac{x+3}{x^3-2x^2+3}dx$
$1-4b+4b^2$
$\frac{3\cdot e^{3x}}{e^{6x}}$
$-\left(7x+11\right)^2$
$\frac{d}{dx}\:y=\frac{10}{x^2+1}$
$\int_{-3}^3\left(\frac{1}{x^2+3}\right)dx$
$x^{-2}\left(x^{\frac{11}{9}}\right)$
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