$5\left(b+3\right)$
$\left(-3ab\right)\left(-3ab^2\right)\left(-3a^2b^2\right)$
$\left(\sin\theta+\cos\theta\right)^{2}=1+\sin2\theta$
$\frac{2x^2-10x-16}{x-6}$
$-2ax+4x+\left(ax\right)^2=0$
$a^3-4x^3+5a^2x-3ax^2-x^3+ax^2-2a^2x$
$3x^4+x^2-2x+1=y$
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