$2y+4y-8$
$\frac{6a^2b^3}{-2a^3b}$
$\int_3^5\left(1x^3-3x^2+4\right)dx$
$5x^2\cdot3xy\cdot2x-6x^3\cdot3x\cdot2y$
$-4c^2+7c+5$
$13-\left|15-\left(6-8\right)\right|+\left(5-9\right)$
$\left(2x^2-32\right)$
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