$\lim_{x\to0}\ln\left(\frac{1+5x}{x}\right)$
$x^2+x+3\le\:9$
$\left(5x^3y\right).\left(3x^2y^5\right)$
$\sqrt{\left(496\right)}$
$\left(2mn^3-2\right)^3$
$f\left(x\right)=\ln\left(\frac{x^2\left(2x-1\right)^3}{\left(x+2\right)^2}\right)$
$x-5<11$
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