$2\cos^2\left(x\right)+2=5\cos\left(x\right)$
$\left(-20\right):\:\left(-10\right)\:+\:\left(-5\right).\:\left(-3\right)$
$\left(b^5+4b^4-14\right)b+1$
$\left(16b^2-81\right)$
$\frac{d}{dx}x^2+2$
$2x^2-x+2=0$
$x^2-2x-8\le0$
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