$\int\left(\frac{1}{x^3}+\frac{1}{x^4}\right)dx$
$\left(d-12\right)\left(d-10\right)$
$10\:-\:-2\:+\:-6\:-20$
$\left(x^2+y^2\right)dx-2xy\:dy=0$
$\left(12x-3y+10\right)-\left(-8x+12\right)$
$\int\cot\left(d\right)$
$\left(3m^3+6p\right)\left(3m^3+2q\right)$
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