$x-1=-20x^2$
$\frac{dy}{dx}=tan\:\left(x+x\right)$
$\frac{x^4-5x^3+3x^2}{x}$
$\int\frac{2x+2}{\left(x^2+1\right)^2\left(x-1\right)^3}dx$
$\left(2x+1\right)^0$
$\int5dc$
$\frac{dy}{dx\:}=\frac{\left(7-y\right)}{x}$
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