$\left(-\frac{1}{3}\left(x\right)^3-4e\left(-8\right)\right)$
$y=3x-8x^2+6$
$3c+10-9-c$
$-7=-1+\frac{x}{3}$
$3x\:x\:x$
$\left(5+2d\right)\left(3+2d\right)$
$-\left|-4+6\right|$
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