$\left(1+\cos^2x\right)\left(1+\tan^2x\right)$
$\frac{3}{2+4x}$
$3w+4+3w+4+4w$
$\lim_{x\to0}\left(ln\left(6x\right)\cdot\arctan\left(2x\right)\right)$
$6x^2+18x$
$4>3x+6$
$\left(63\right)\cdot\left(-4\right)$
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