$\left(-7x^2+3x+5\right)+\left(5x^2-8x+4\right)-\left(-2x^2-6x+6\right)$
$\left(y-x\right)y^{'\:}=y-x+8$
$\frac{3x^2+2x-8}{x^2+2}$
$5x^6+x^4+3x$
$10^3\:-\left(5^4\right)$
$\int_1^4\left(\frac{x-1}{2x^2-13x-7}\right)dx$
$\sqrt{\frac{225}{625}m^4\:n^6}$
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