$\lim_{x\to-\infty}\left(\frac{x^2-2x}{3}\right)$
$\left(x-2\right)^4>\:0$
$\int\frac{10x^2-40x+12}{x\left(x+1\right)^2}dx$
$4\cos\left(x\right)=-2\sqrt{3}$
$12\cdot10+15$
$\cos\left(x-\pi\right)=\cos\left(x\right)$
$3x^4+3xy^4z^2$
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