$\frac{4x^3-3x-24}{8}$

$\int\left(\frac{x}{ye^x}\right)\:dx$

$\frac{5x^2y^2}{4xy^2}$

$\left(1\right)^5+\left(1\right)^4+\left(1\right)^3-\left(1\right)^2-\left(1\right)-1$

$\int10\left(q+10\right)e^{-0.1q-1}-14.94dx$

$6x+5y\frac{dy}{dx}=0$

$\tan\left(x+y\right)=\frac{\tan\left(x\right)+\tan\left(y\right)}{1-\tan\left(x\right)\cdot\tan\left(y\right)}$