$9m^2-1$
$\int \thetadx$
$\frac{x^2-1}{x^2+5}\ge1$
$x\left(y^2+1\right)^{\left(\frac{3}{2}\right)}dx=e^{x^2}ydy$
$y'+6\cdot y=8\cdot e^{\left(8\cdot x\right)}$
$+4-13+2-23+3-1+16-17-2-5$
$-45\cdot17$
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