$\sqrt[6]{3^{-4}}$
$2x^2<2x-3$
$6x^2+5\:x+1$
$\left|\left(3\right)^2-4\right|$
$\lim_{x\to\infty}x\sqrt{x^2+1-x}$
$\left(x-14\right)\left(x+21\right)$
$\left(x-10\right)\left(x-11\right)$
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