$\left(16x^3\:+\:8\right)\left(4x\:+\:2\right)$
$w^{-2}w^{-3}w^6$
$\int\frac{x^3-6x^2+x-4}{1-x^4}dx$
$-2\left(p-5\right)$
$-8\left(-3+8x\right)=-232$
$5\left(3+2k\right)$
$\frac{2}{x+1}=\frac{3}{x+2}$
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