$2\sqrt{48}$
$4y^8+140y^4z^4+100z^8$
$\frac{8w^3h^4}{4wh^2}$
$\lim_{x\to0}\left(\left(e^x-x\right)^{\left(\frac{1}{x}\right)}\right)$
$x-18+x-20$
$16^1$
$\left(4y^2+9y-1\right)\cdot\left(5y\right)$
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